What is expand (asin(b)+lsin(θ))^2 ?

The solution to expand (asin(b)+lsin(θ))^2 is a^2sin^2(b)+2alsin(b)sin(θ)+l^2sin^2(θ)

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expand (asin(b)+lsin(θ))^2

expand

(a sin (b) + l sin (θ))^{2}

a^{2} sin^{2} (b) + 2 a l sin (b) sin (θ) + l^{2} sin^{2} (θ)

Solution steps

(a sin (b) + l sin (θ))^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(a sin (b) + l sin (θ))^{2} = (a sin (b))^{2} + 2 a sin (b) l sin (θ) + (l sin (θ))^{2}

= (a sin (b))^{2} + 2 a sin (b) l sin (θ) + (l sin (θ))^{2}

Simplify

(a sin (b))^{2} + 2 a sin (b) l sin (θ) + (l sin (θ))^{2} : a^{2} sin^{2} (b) + 2 a l sin (b) sin (θ) + l^{2} sin^{2} (θ)

= a^{2} sin^{2} (b) + 2 a l sin (b) sin (θ) + l^{2} sin^{2} (θ)

(- sin (2 x) + 3 sin (x))^{2} (- 2 sin (2 x) - 3 sin (x))

20 (\frac{6}{5} - \frac{6}{5} e^{- 20 t})

\frac{3 j ( 4 + j ^{4} )}{8 - j ^{8}}

(\frac{1}{4} x^{2} - \frac{1}{x ^{2}})^{2}

\frac{A}{S + 1} \cdot (S + 1) (S - 1) (S + 2) (S^{2} + 1)

What is expand (asin(b)+lsin(θ))^2 ?
The solution to expand (asin(b)+lsin(θ))^2 is a^2sin^2(b)+2alsin(b)sin(θ)+l^2sin^2(θ)