What is expand (rcos(θ)+rsin(θ))r ?

The solution to expand (rcos(θ)+rsin(θ))r is r^2cos(θ)+r^2sin(θ)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (rcos(θ)+rsin(θ))r

expand

(r cos (θ) + r sin (θ)) r

r^{2} cos (θ) + r^{2} sin (θ)

Solution steps

(r cos (θ) + r sin (θ)) r

= r (r cos (θ) + r sin (θ))

Apply the distributive law:

a (b + c) = ab + a c

r (r cos (θ) + r sin (θ)) = rr cos (θ) + rr sin (θ)

= rr cos (θ) + rr sin (θ)

Simplify

rr cos (θ) + rr sin (θ) : r^{2} cos (θ) + r^{2} sin (θ)

= r^{2} cos (θ) + r^{2} sin (θ)

\frac{1}{x ^{2} ( x + 4 )}

e^{(1 + i) z}

\frac{( x ^{2} - 14 x - 3 )}{( x ^{2} + 1 ) \cdot ( x - 3 )}

\frac{5 ( 3 + 3 )}{6}

\frac{7 x ^{2} - 2 x - 6}{( 2 x - 1 ) ( x ^{2} - 2 )}

What is expand (rcos(θ)+rsin(θ))r ?
The solution to expand (rcos(θ)+rsin(θ))r is r^2cos(θ)+r^2sin(θ)