What is expand-1/4 (t+3ln|t|)+C ?

The solution to expand-1/4 (t+3ln|t|)+C is -t/4-(3ln|t|)/4+C

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expand-1/4 (t+3ln|t|)+C

expand

- \frac{1}{4} (t + 3 ln ∣ t ∣) + C

- \frac{t}{4} - \frac{3 ln ∣ t ∣}{4} + C

Solution steps

- \frac{1}{4} (t + 3 ln ∣ t ∣) + C

Expand

- \frac{1}{4} (t + 3 ln ∣ t ∣) : - \frac{t}{4} - \frac{3 ln ∣ t ∣}{4}

= - \frac{t}{4} - \frac{3 ln ∣ t ∣}{4} + C

\frac{x + 1 + x ^{2}}{x ^{2} ( x ^{2} + 2 x + 5 )}

(x - 1 + 7) (x - 1 - 7)

(z + \frac{3}{5}) (z - \frac{3}{5})

(x^{2} - \frac{1}{4})^{2}

What is expand-1/4 (t+3ln|t|)+C ?
The solution to expand-1/4 (t+3ln|t|)+C is -t/4-(3ln|t|)/4+C