What is expand p^1(1/2-((p^1-p^2))/(2t)) ?

The solution to expand p^1(1/2-((p^1-p^2))/(2t)) is p/2-(p(p-p^2))/(2t)

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expand p^1(1/2-((p^1-p^2))/(2t))

expand

p^{1} (\frac{1}{2} - \frac{( p ^{1} - p ^{2} )}{2 t})

\frac{p}{2} - \frac{p ( p - p ^{2} )}{2 t}

Solution steps

p^{1} (\frac{1}{2} - \frac{p ^{1} - p ^{2}}{2 t})

Apply the distributive law:

a (b - c) = ab - a c

p^{1} (\frac{1}{2} - \frac{p ^{1} - p ^{2}}{2 t}) = p^{1} \frac{1}{2} - p^{1} \frac{p ^{1} - p ^{2}}{2 t}

= p^{1} \frac{1}{2} - p^{1} \frac{p ^{1} - p ^{2}}{2 t}

Simplify

p^{1} \frac{1}{2} - p^{1} \frac{p ^{1} - p ^{2}}{2 t} : \frac{p}{2} - \frac{p ( p - p ^{2} )}{2 t}

= \frac{p}{2} - \frac{p ( p - p ^{2} )}{2 t}

(3 x + 2 y = 0,) (2 x - 3 y = 13,)

(e^{i θ} - e^{- i θ})^{3}

23 (3 + 10)

x (2 sin (x) + x cos (x))

x^{\frac{1}{3}} (2 x - 2)

What is expand p^1(1/2-((p^1-p^2))/(2t)) ?
The solution to expand p^1(1/2-((p^1-p^2))/(2t)) is p/2-(p(p-p^2))/(2t)