What is expand ((z-1)^3)/(2(z+2)^2) ?

The solution to expand ((z-1)^3)/(2(z+2)^2) is (z^3-3z^2+3z-1)/(2z^2+8z+8)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((z-1)^3)/(2(z+2)^2)

expand

\frac{( z - 1 ) ^{3}}{2 ( z + 2 ) ^{2}}

\frac{z ^{3} - 3 z ^{2} + 3 z - 1}{2 z ^{2} + 8 z + 8}

Solution steps

\frac{( z - 1 ) ^{3}}{2 ( z + 2 ) ^{2}}

(z + 2)^{2} = z^{2} + 4 z + 4

= \frac{( z - 1 ) ^{3}}{2 ( z ^{2} + 4 z + 4 )}

(z - 1)^{3} = z^{3} - 3 z^{2} + 3 z - 1

= \frac{z ^{3} - 3 z ^{2} + 3 z - 1}{2 ( z ^{2} + 4 z + 4 )}

Expand

2 (z^{2} + 4 z + 4) : 2 z^{2} + 8 z + 8

= \frac{z ^{3} - 3 z ^{2} + 3 z - 1}{2 z ^{2} + 8 z + 8}

12

\frac{d ^{2}}{d y d x} ((z (y, x)) (x^{2} + 3 x y + y^{2}))

- 8 (3 + 10)

x^{2} - (3 + 5) x + 4

(\frac{3}{a + 1} - 1) \cdot (\frac{3}{2 - a} - 1)

What is expand ((z-1)^3)/(2(z+2)^2) ?
The solution to expand ((z-1)^3)/(2(z+2)^2) is (z^3-3z^2+3z-1)/(2z^2+8z+8)