What is expand (1-2sin(θ))^2 ?

The solution to expand (1-2sin(θ))^2 is 1-4sin(θ)+4sin^2(θ)

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expand (1-2sin(θ))^2

expand

(1 - 2 sin (θ))^{2}

1 - 4 sin (θ) + 4 sin^{2} (θ)

Solution steps

(1 - 2 sin (θ))^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(1 - 2 sin (θ))^{2} = 1^{2} - 2 \cdot 1 \cdot 2 sin (θ) + (2 sin (θ))^{2}

= 1^{2} - 2 \cdot 1 \cdot 2 sin (θ) + (2 sin (θ))^{2}

Simplify

1^{2} - 2 \cdot 1 \cdot 2 sin (θ) + (2 sin (θ))^{2} : 1 - 4 sin (θ) + 4 sin^{2} (θ)

= 1 - 4 sin (θ) + 4 sin^{2} (θ)

6.16 + 0.22 e^{- e^{(- 0.65) (t - 1.22)}}

(x - 2) lo g_{2} (3) - 3 x

(3 e^{2} - 5 a) (5 a + 3 e^{2})

(2 - \frac{1}{2} x)^{2}

\frac{e ^{- s}}{s ( s ^{2} - 5 s + 6 )} + \frac{1}{s ^{2} - 5 s + 6}

What is expand (1-2sin(θ))^2 ?
The solution to expand (1-2sin(θ))^2 is 1-4sin(θ)+4sin^2(θ)