What is expand (1/k y+b/2)^2 ?

The solution to expand (1/k y+b/2)^2 is (4y^2+4ybk+b^2k^2)/(4k^2)

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expand (1/k y+b/2)^2

expand

(\frac{1}{k} y + \frac{b}{2})^{2}

\frac{4 y ^{2} + 4 y bk + b ^{2} k ^{2}}{4 k ^{2}}

Solution steps

(\frac{1}{k} y + \frac{b}{2})^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(\frac{1}{k} y + \frac{b}{2})^{2} = (\frac{1}{k} y)^{2} + 2 \cdot \frac{1}{k} y \frac{b}{2} + (\frac{b}{2})^{2}

= (\frac{1}{k} y)^{2} + 2 \cdot \frac{1}{k} y \frac{b}{2} + (\frac{b}{2})^{2}

Simplify

(\frac{1}{k} y)^{2} + 2 \cdot \frac{1}{k} y \frac{b}{2} + (\frac{b}{2})^{2} : \frac{4 y ^{2} + 4 y bk + b ^{2} k ^{2}}{4 k ^{2}}

= \frac{4 y ^{2} + 4 y bk + b ^{2} k ^{2}}{4 k ^{2}}

\frac{5 ( x - 2 )}{3}

π (- 16 + x^{2})

\frac{( 8 s ^{2} - 4 s + 12 )}{s ( s ^{2} + 4 )}

3 (x^{2} + y^{2}) d x + x (x^{2} + 3 y^{2} + 6 y) d y

\frac{2 - x}{x ^{2} + 4 x + 4} + \frac{1}{x + 2}

What is expand (1/k y+b/2)^2 ?
The solution to expand (1/k y+b/2)^2 is (4y^2+4ybk+b^2k^2)/(4k^2)