What is expand (-2x^2-2x+4)/((2x+1)^2) ?

The solution to expand (-2x^2-2x+4)/((2x+1)^2) is (-2x^2-2x+4)/(4x^2+4x+1)

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expand (-2x^2-2x+4)/((2x+1)^2)

expand

\frac{- 2 x ^{2} - 2 x + 4}{( 2 x + 1 ) ^{2}}

\frac{- 2 x ^{2} - 2 x + 4}{4 x ^{2} + 4 x + 1}

Solution steps

\frac{- 2 x ^{2} - 2 x + 4}{( 2 x + 1 ) ^{2}}

(2 x + 1)^{2} = 4 x^{2} + 4 x + 1

= \frac{- 2 x ^{2} - 2 x + 4}{4 x ^{2} + 4 x + 1}

(6 - 2 r^{2}) (2 - 8 r^{3} cos (θ) sin (θ))

\frac{3 ( 21 - 41 )}{16}

(\frac{( q - p )}{2})^{2} + q \cdot p

\frac{x ^{2} + 2}{x ^{2} ( x ^{2} + 4 )}

r cos (θ) (r cos (θ) - 2)

What is expand (-2x^2-2x+4)/((2x+1)^2) ?
The solution to expand (-2x^2-2x+4)/((2x+1)^2) is (-2x^2-2x+4)/(4x^2+4x+1)