What is expand ((4x+1)^2)/((x-2)(x+3)) ?

The solution to expand ((4x+1)^2)/((x-2)(x+3)) is (16x^2+8x+1)/(x^2+x-6)

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expand ((4x+1)^2)/((x-2)(x+3))

expand

\frac{( 4 x + 1 ) ^{2}}{( x - 2 ) ( x + 3 )}

\frac{16 x ^{2} + 8 x + 1}{x ^{2} + x - 6}

Solution steps

\frac{( 4 x + 1 ) ^{2}}{( x - 2 ) ( x + 3 )}

(4 x + 1)^{2} = 16 x^{2} + 8 x + 1

= \frac{16 x ^{2} + 8 x + 1}{( x - 2 ) ( x + 3 )}

Expand

(x - 2) (x + 3) : x^{2} + x - 6

= \frac{16 x ^{2} + 8 x + 1}{x ^{2} + x - 6}

d x [x (5 x^{4} - 7 x^{2} - 3)]

sin (\frac{x}{2}) (2 sin (\frac{x}{2}) - 1)

(y + 1) e^{x}

(2 x + \frac{1}{3 x})^{18}

x^{2} (ln (x + 2) - 1) d x

What is expand ((4x+1)^2)/((x-2)(x+3)) ?
The solution to expand ((4x+1)^2)/((x-2)(x+3)) is (16x^2+8x+1)/(x^2+x-6)