What is expand-1/((e^t+e^{-t))^2} ?

The solution to expand-1/((e^t+e^{-t))^2} is -1/(e^{2t)+2+e^{-2t}}

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expand-1/((e^t+e^{-t))^2}

expand

- \frac{1}{( e ^{t} + e ^{- t} ) ^{2}}

- \frac{1}{e ^{2 t} + 2 + e ^{- 2 t}}

Solution steps

- \frac{1}{( e ^{t} + e ^{- t} ) ^{2}}

(e^{t} + e^{- t})^{2} = e^{2 t} + 2 + e^{- 2 t}

= - \frac{1}{e ^{2 t} + e ^{- 2 t} + 2}

\frac{1}{25} (- 5 t + e^{5 t} - 1)

\frac{\frac{4 x}{x + 1}}{\frac{3 x ^{4}}{x ^{2} - 1}}

ln (x) (x + 9)

(1 - x - 3)^{2}

(e^{3 x}) (e^{3 x} + 3 x e^{3 x})

What is expand-1/((e^t+e^{-t))^2} ?
The solution to expand-1/((e^t+e^{-t))^2} is -1/(e^{2t)+2+e^{-2t}}