What are the solutions to the equation 5x^2+1=6x ?

The solutions to the equation 5x^2+1=6x are x=1,x= 1/5

Find the zeros of 5x^2+1=6x

The zeros of 5x^2+1=6x are x=1,x= 1/5

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5 x^{2} + 1 = 6 x

x = 1, x = \frac{1}{5}

Decimal Notation

x = 1, x = 0.2

Solution steps

5 x^{2} + 1 = 6 x

Move

6 x

to the left side

5 x^{2} + 1 - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 5 \cdot 1}{2 \cdot 5}

(- 6)^{2} - 4 \cdot 5 \cdot 1 = 4

x_{1, 2} = \frac{- ( - 6 ) \pm 4}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 4}{2 \cdot 5}, x_{2} = \frac{- ( - 6 ) - 4}{2 \cdot 5}

x = \frac{- ( - 6 ) + 4}{2 \cdot 5} : 1

x = \frac{- ( - 6 ) - 4}{2 \cdot 5} : \frac{1}{5}

The solutions to the quadratic equation are:

x = 1, x = \frac{1}{5}

- 10 s + 2 (- 2 s - 9) \leq 3 s - 1 + 7 s

\frac{1}{x + h} - \frac{1}{x}

x^{2} 10 x^{2} - 3 x - 4

\frac{4 ( x - 3 )}{5} = 3 (x + 2)

\frac{x ^{6}}{x ^{2}}

What are the solutions to the equation 5x^2+1=6x ?
The solutions to the equation 5x^2+1=6x are x=1,x= 1/5
Find the zeros of 5x^2+1=6x
The zeros of 5x^2+1=6x are x=1,x= 1/5