What is expand (e^x+e^xx)(e^x) ?

The solution to expand (e^x+e^xx)(e^x) is e^{2x}+e^{2x}x

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expand (e^x+e^xx)(e^x)

expand

(e^{x} + e^{x} x) (e^{x})

e^{2 x} + e^{2 x} x

Solution steps

(e^{x} + e^{x} x) (e^{x})

= (e^{x}) (e^{x} + e^{x} x)

Apply the distributive law:

a (b + c) = ab + a c

a = (e^{x}), b = e^{x}, c = e^{x} x

= (e^{x}) e^{x} + (e^{x}) e^{x} x

= e^{x} (e^{x}) + e^{x} x (e^{x})

Simplify

e^{x} (e^{x}) + e^{x} x (e^{x}) : e^{2 x} + e^{2 x} x

= e^{2 x} + e^{2 x} x

[cos (7 t) (5 + sinh (\frac{3 t}{2}) + e^{2 t})]

\frac{d}{d x} ((e^{x}) (5 e^{5 x} - 25 x))

(4 x - 8 y = - 1, 4) (2 x - 4 y = - 7)

(2 x - 6 x y^{3}) (e^{t})

2 l e f t (3, 4, 5) - 3 l e f t (- 1, - 2, - 3)

What is expand (e^x+e^xx)(e^x) ?
The solution to expand (e^x+e^xx)(e^x) is e^{2x}+e^{2x}x