What is expand (s^2+x)/((s+1)(s-1)(s-4)) ?

The solution to expand (s^2+x)/((s+1)(s-1)(s-4)) is (s^2+x)/(s^3-4s^2-s+4)

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expand (s^2+x)/((s+1)(s-1)(s-4))

expand

\frac{s ^{2} + x}{( s + 1 ) ( s - 1 ) ( s - 4 )}

\frac{s ^{2} + x}{s ^{3} - 4 s ^{2} - s + 4}

Solution steps

\frac{s ^{2} + x}{( s + 1 ) ( s - 1 ) ( s - 4 )}

Expand

(s + 1) (s - 1) (s - 4) : s^{3} - 4 s^{2} - s + 4

= \frac{s ^{2} + x}{s ^{3} - 4 s ^{2} - s + 4}

I n (\frac{e ^{2}}{12})

8 (1 - 3 π) c m^{2}

(x^{2})^{\frac{1}{2}}

(2 x - 3 x)^{2}

(x y^{2} + y) d x

What is expand (s^2+x)/((s+1)(s-1)(s-4)) ?
The solution to expand (s^2+x)/((s+1)(s-1)(s-4)) is (s^2+x)/(s^3-4s^2-s+4)