What is cos^2(x)-cos(2x)(1/2 (1+cos(4x))) ?

The solution to cos^2(x)-cos(2x)(1/2 (1+cos(4x))) is cos^2(x)-(cos(2x)(1+cos(4x)))/2

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simplify cos^2(x)-cos(2x)(1/2 (1+cos(4x)))

simplify

cos^{2} (x) - cos (2 x) (\frac{1}{2} (1 + cos (4 x)))

cos^{2} (x) - \frac{cos ( 2 x ) ( 1 + cos ( 4 x ) )}{2}

Solution steps

cos^{2} (x) - cos (2 x) (\frac{1}{2} (1 + cos (4 x)))

Expand

\frac{1}{2} (1 + cos (4 x)) : \frac{1 + cos ( 4 x )}{2}

= cos^{2} (x) - cos (2 x) \frac{1 + cos ( 4 x )}{2}

Simplify

cos (2 x) \frac{1 + cos ( 4 x )}{2} : \frac{cos ( 2 x ) ( 1 + cos ( 4 x ) )}{2}

= cos^{2} (x) - \frac{cos ( 2 x ) ( 1 + cos ( 4 x ) )}{2}

16777216 π (\frac{1}{2} ln (2 + 5) + 5)

x (x^{3} + 3 x^{2} d x + 3 x d x^{2} + d x^{3} + 1)

(1.2 b + 4.32) (\frac{1.2 b + 4.32}{b + 7.59})^{\frac{2}{3}}

(x - 3)^{2} x

x^{\frac{2}{a}} (x^{2 a} + 1)

What is cos^2(x)-cos(2x)(1/2 (1+cos(4x))) ?
The solution to cos^2(x)-cos(2x)(1/2 (1+cos(4x))) is cos^2(x)-(cos(2x)(1+cos(4x)))/2