What is expand (x^2-1-sqrt(3))^3 ?

The solution to expand (x^2-1-sqrt(3))^3 is x^6-3x^4(1+sqrt(3))+6x^2(2+sqrt(3))-6sqrt(3)-10

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expand (x^2-1-sqrt(3))^3

expand

(x^{2} - 1 - 3)^{3}

x^{6} - 3 x^{4} (1 + 3) + 6 x^{2} (2 + 3) - 63 - 10

Solution steps

(x^{2} - 1 - 3)^{3}

Simplify

(x^{2} - 1 - 3)^{3} : (x^{2} - 1 - 3) (x^{2} - 1 - 3) (x^{2} - 1 - 3)

= (x^{2} - 1 - 3) (x^{2} - 1 - 3) (x^{2} - 1 - 3)

Expand

(x^{2} - 1 - 3) (x^{2} - 1 - 3) : x^{4} - 2 x^{2} (1 + 3) + 23 + 4

= (x^{4} - 2 x^{2} (1 + 3) + 23 + 4) (x^{2} - 1 - 3)

Distribute parentheses

= x^{4} x^{2} + x^{4} (- 1) + x^{4} (- 3) - 2 x^{2} (1 + 3) x^{2} - 2 x^{2} (1 + 3) (- 1) - 2 x^{2} (1 + 3) (- 3) + 23 x^{2} + 23 (- 1) + 23 (- 3) + 4 x^{2} + 4 (- 1) + 4 (- 3)

Simplify

x^{4} x^{2} + x^{4} (- 1) + x^{4} (- 3) - 2 x^{2} (1 + 3) x^{2} - 2 x^{2} (1 + 3) (- 1) - 2 x^{2} (1 + 3) (- 3) + 23 x^{2} + 23 (- 1) + 23 (- 3) + 4 x^{2} + 4 (- 1) + 4 (- 3) : x^{6} - 3 x^{4} (1 + 3) + 6 x^{2} (2 + 3) - 63 - 10

= x^{6} - 3 x^{4} (1 + 3) + 6 x^{2} (2 + 3) - 63 - 10

(y + 1) d x - x d y

\frac{2 ( a + b )}{a - b}

(6 - 3 x^{3} + 6)^{2}

(- 2 sin (x) + 1) (sin (x) + 1)

What is expand (x^2-1-sqrt(3))^3 ?
The solution to expand (x^2-1-sqrt(3))^3 is x^6-3x^4(1+sqrt(3))+6x^2(2+sqrt(3))-6sqrt(3)-10