What is expand (-3a^2b+8b)(-9a+5)^' ?

The solution to expand (-3a^2b+8b)(-9a+5)^' is -3a^2b(-9a+5)^'+8b(-9a+5)^'

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (-3a^2b+8b)(-9a+5)^'

expand

(- 3 a^{2} b + 8 b) (- 9 a + 5)^{^{'}}

- 3 a^{2} b (- 9 a + 5)^{'} + 8 b (- 9 a + 5)^{'}

Solution steps

(- 3 a^{2} b + 8 b) (- 9 a + 5)^{^{'}}

Apply the distributive law:

a (b + c) = ab + a c

a = (- 9 a + 5)^{^{'}}, b = - 3 a^{2} b, c = 8 b

= (- 9 a + 5)^{^{^{'}}} (- 3 a^{2} b) + (- 9 a + 5)^{^{^{'}}} \cdot 8 b

Apply minus-plus rules

+ (- a) = - a

= - 3 a^{2} b (- 9 a + 5)^{^{^{'}}} + 8 b (- 9 a + 5)^{^{^{'}}}

c (2, - 3)

(5 + 7 x) x^{4} e^{7 x}

(7 x - 19) sin (x^{2} - 4 x + 4)

1 + \frac{5 ( \frac{0.5}{s} + 0.5 )}{( 2 s + 1 ) ( 0.1 s + 1 )}

What is expand (-3a^2b+8b)(-9a+5)^' ?
The solution to expand (-3a^2b+8b)(-9a+5)^' is -3a^2b(-9a+5)^'+8b(-9a+5)^'