What is expand-1/((x+4)(x+1)x^2) ?

The solution to expand-1/((x+4)(x+1)x^2) is -1/(x^4+5x^3+4x^2)

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expand-1/((x+4)(x+1)x^2)

expand

- \frac{1}{( x + 4 ) ( x + 1 ) x ^{2}}

- \frac{1}{x ^{4} + 5 x ^{3} + 4 x ^{2}}

Solution steps

- \frac{1}{( x + 4 ) ( x + 1 ) x ^{2}}

Expand

(x + 4) (x + 1) x^{2} : x^{4} + 5 x^{3} + 4 x^{2}

= - \frac{1}{x ^{4} + 5 x ^{3} + 4 x ^{2}}

(x + 2 y - 2) d x + (2 x - y + 3) d y

(4 x - 1) (6 + 7 x)

(2 π x) (2 x + e^{x})

4 (2 cos^{2} (φ) - \frac{sec ^{2} ( φ )}{2}) \cdot sin (φ)

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What is expand-1/((x+4)(x+1)x^2) ?
The solution to expand-1/((x+4)(x+1)x^2) is -1/(x^4+5x^3+4x^2)