What is expand-4(2xe^{2x}+e^{2x}*2x^2) ?

The solution to expand-4(2xe^{2x}+e^{2x}*2x^2) is -8e^{2x}x-8e^{2x}x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-4(2xe^{2x}+e^{2x}*2x^2)

expand

- 4 (2 x e^{2 x} + e^{2 x} \cdot 2 x^{2})

- 8 e^{2 x} x - 8 e^{2 x} x^{2}

Solution steps

- 4 (2 x e^{2 x} + e^{2 x} \cdot 2 x^{2})

= - 4 (2 e^{2 x} x + 2 e^{2 x} x^{2})

Apply the distributive law:

a (b + c) = ab + a c

a = - 4, b = 2 x e^{2 x}, c = e^{2 x} \cdot 2 x^{2}

= - 4 \cdot 2 x e^{2 x} + (- 4) e^{2 x} \cdot 2 x^{2}

Apply minus-plus rules

+ (- a) = - a

= - 4 \cdot 2 e^{2 x} x - 4 \cdot 2 e^{2 x} x^{2}

Multiply the numbers:

4 \cdot 2 = 8

= - 8 e^{2 x} x - 8 e^{2 x} x^{2}

lo g_{2} (8 x^{(2)} + 80 x + 200)

\frac{( s + 2 ) ^{2}}{s ( s + 1 ) ^{3}}

2 (4 x)

\frac{( x - 1 ) ( x ^{2} + x + 1 )}{x ^{3}}

(6 x^{2} - 8 ν x^{2} + v^{2} x^{2}) (ν d x + x d v)

What is expand-4(2xe^{2x}+e^{2x}*2x^2) ?
The solution to expand-4(2xe^{2x}+e^{2x}*2x^2) is -8e^{2x}x-8e^{2x}x^2