What is expand-derivative of ((x^2-4^2)x) ?

The solution to expand-derivative of ((x^2-4^2)x) is -derivative of x^5-8x^3+16x

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expand-derivative of ((x^2-4^2)x)

expand

- \frac{d}{d x} (((x^{2} - 4)^{2}) x)

- \frac{d}{d x} (x^{5} - 8 x^{3} + 16 x)

Solution steps

- \frac{d}{d x} (((x^{2} - 4)^{2}) x)

Remove parentheses:

(a) = a

= - \frac{d}{d x} ((x^{2} - 4)^{2} x)

(x^{2} - 4)^{2} = x^{4} - 8 x^{2} + 16

= - \frac{d}{d x} (x (x^{4} - 8 x^{2} + 16))

Expand

(x^{4} - 8 x^{2} + 16) x : x^{5} - 8 x^{3} + 16 x

= - \frac{d}{d x} (x^{5} - 8 x^{3} + 16 x)

(\exists x) (\forall y) (x + 2 y = 3)

\frac{- 4 x + 10}{( x - 2 ) ( x + 8 )}

5 (8 + 2)

(e^{x - y} + 1 - \frac{x ^{2}}{y ^{2}}) (\frac{1}{2})

(2 - x - x)^{2}

What is expand-derivative of ((x^2-4^2)x) ?
The solution to expand-derivative of ((x^2-4^2)x) is -derivative of x^5-8x^3+16x