What is (d^2)/(dt^2)((x)(cos(2t)+sin(2t)+1/5 e^t)) ?

The answer to (d^2)/(dt^2)((x)(cos(2t)+sin(2t)+1/5 e^t)) is x(-4cos(2t)-4sin(2t)+1/5 e^t)

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(d^2)/(dt^2)((x)(cos(2t)+sin(2t)+1/5 e^t))

\frac{d ^{2}}{d t ^{2}} ((x) (cos (2 t) + sin (2 t) + \frac{1}{5} e^{t}))

x (- 4 cos (2 t) - 4 sin (2 t) + \frac{1}{5} e^{t})

Solution steps

\frac{d ^{2}}{d t ^{2}} ((x) (cos (2 t) + sin (2 t) + \frac{1}{5} e^{t}))

\frac{d}{d t} (x (cos (2 t) + sin (2 t) + \frac{1}{5} e^{t})) = x (- sin (2 t) \cdot 2 + cos (2 t) \cdot 2 + \frac{1}{5} e^{t})

= \frac{d}{d t} (x (- sin (2 t) \cdot 2 + cos (2 t) \cdot 2 + \frac{1}{5} e^{t}))

\frac{d}{d t} (x (- sin (2 t) \cdot 2 + cos (2 t) \cdot 2 + \frac{1}{5} e^{t})) = x (- 4 cos (2 t) - 4 sin (2 t) + \frac{1}{5} e^{t})

= x (- 4 cos (2 t) - 4 sin (2 t) + \frac{1}{5} e^{t})

- 3 (x - \frac{π}{3})

\frac{\partial}{\partial x} ((z) (x y - 2 x + 5 y))

(2 x - y) (3 x + 5 y)

lo g_{10} (1)

(3 u - \frac{3}{11} v)^{2}

What is (d^2)/(dt^2)((x)(cos(2t)+sin(2t)+1/5 e^t)) ?
The answer to (d^2)/(dt^2)((x)(cos(2t)+sin(2t)+1/5 e^t)) is x(-4cos(2t)-4sin(2t)+1/5 e^t)