What is expand (x+1)ln^2(x+1) ?

The solution to expand (x+1)ln^2(x+1) is xln^2(x+1)+ln^2(x+1)

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expand (x+1)ln^2(x+1)

expand

(x + 1) ln^{2} (x + 1)

x ln^{2} (x + 1) + ln^{2} (x + 1)

Solution steps

(x + 1) ln^{2} (x + 1)

= ln^{2} (x + 1) (x + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = ln^{2} (x + 1), b = x, c = 1

= ln^{2} (x + 1) x + ln^{2} (x + 1) \cdot 1

= x ln^{2} (x + 1) + 1 \cdot ln^{2} (x + 1)

Multiply:

1 \cdot ln^{2} (x + 1) = ln^{2} (x + 1)

= x ln^{2} (x + 1) + ln^{2} (x + 1)

(1 + 2)^{3}

sin (x) cos (π) - cos (x) sin (π)

\frac{8 - 3 x}{3 x ^{\frac{1}{3}} ( 4 - x ) ^{\frac{5}{3}}}

\frac{x ^{2}}{( 0.860708 - 1.8560668 x + x ^{2} ) \cdot ( x - 1 )}

- \frac{2 ( 2 x ^{4} - 1 )}{x ^{4}}

What is expand (x+1)ln^2(x+1) ?
The solution to expand (x+1)ln^2(x+1) is xln^2(x+1)+ln^2(x+1)