What is expand (-t^3+9/10 t+1/10)(1+t+t^2) ?

The solution to expand (-t^3+9/10 t+1/10)(1+t+t^2) is -(t^3)/(10)-t^4-t^5+t+t^2+1/10

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expand (-t^3+9/10 t+1/10)(1+t+t^2)

expand

(- t^{3} + \frac{9}{10} t + \frac{1}{10}) (1 + t + t^{2})

- \frac{t ^{3}}{10} - t^{4} - t^{5} + t + t^{2} + \frac{1}{10}

Solution steps

(- t^{3} + \frac{9}{10} t + \frac{1}{10}) (1 + t + t^{2})

Distribute parentheses

= - t^{3} \cdot 1 - t^{3} t - t^{3} t^{2} + \frac{9}{10} t \cdot 1 + \frac{9}{10} tt + \frac{9}{10} t t^{2} + \frac{1}{10} \cdot 1 + \frac{1}{10} t + \frac{1}{10} t^{2}

Simplify

- t^{3} \cdot 1 - t^{3} t - t^{3} t^{2} + \frac{9}{10} t \cdot 1 + \frac{9}{10} tt + \frac{9}{10} t t^{2} + \frac{1}{10} \cdot 1 + \frac{1}{10} t + \frac{1}{10} t^{2} : - \frac{t ^{3}}{10} - t^{4} - t^{5} + t + t^{2} + \frac{1}{10}

= - \frac{t ^{3}}{10} - t^{4} - t^{5} + t + t^{2} + \frac{1}{10}

\frac{x ( x + 6 )}{2 ( x - 3 )}

11 (\frac{3}{5} x + \frac{4}{5} y)

L im x \Rightarrow 3 (13 x^{2} - 27)

\frac{100}{98}

4 \cdot π \cdot (2 + ln (2 + 1))

What is expand (-t^3+9/10 t+1/10)(1+t+t^2) ?
The solution to expand (-t^3+9/10 t+1/10)(1+t+t^2) is -(t^3)/(10)-t^4-t^5+t+t^2+1/10