What is expand (e^x-1/(e^x))(e^x+1/(e^x)) ?

The solution to expand (e^x-1/(e^x))(e^x+1/(e^x)) is e^{2x}-1/(e^{2x)}

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expand (e^x-1/(e^x))(e^x+1/(e^x))

expand

(e^{x} - \frac{1}{e ^{x}}) (e^{x} + \frac{1}{e ^{x}})

e^{2 x} - \frac{1}{e ^{2 x}}

Solution steps

(e^{x} - \frac{1}{e ^{x}}) (e^{x} + \frac{1}{e ^{x}})

Apply Difference of Two Squares Formula:

(a - b) (a + b) = a^{2} - b^{2}

a = e^{x}, b = \frac{1}{e ^{x}}

= (e^{x})^{2} - (\frac{1}{e ^{x}})^{2}

Simplify

(e^{x})^{2} - (\frac{1}{e ^{x}})^{2} : e^{2 x} - \frac{1}{e ^{2 x}}

= e^{2 x} - \frac{1}{e ^{2 x}}

\frac{s ^{4} + 81}{s ( s ^{2} + 9 ) ^{2}}

(y + x) d x

(10 sin (x) - 1) (10 sin (x) + 1)

\frac{( 5 - x ) ^{2}}{2}

n (\frac{ln ( n + 1 )}{ln ( n )} - 1)

What is expand (e^x-1/(e^x))(e^x+1/(e^x)) ?
The solution to expand (e^x-1/(e^x))(e^x+1/(e^x)) is e^{2x}-1/(e^{2x)}