What is (s^2+4)*(s^2+4/3) ?

The solution to (s^2+4)*(s^2+4/3) is ((s^2+4)(3s^2+4))/3

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simplify (s^2+4)*(s^2+4/3)

simplify

(s^{2} + 4) \cdot (s^{2} + \frac{4}{3})

\frac{( s ^{2} + 4 ) ( 3 s ^{2} + 4 )}{3}

Solution steps

(s^{2} + 4) (s^{2} + \frac{4}{3})

Simplify

s^{2} + \frac{4}{3} : \frac{3 s ^{2} + 4}{3}

= (s^{2} + 4) \frac{3 s ^{2} + 4}{3}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( s ^{2} + 4 ) ( 3 s ^{2} + 4 )}{3}

(- 3 x + 2 + 1)^{2}

\frac{( - y + 4 ) ^{3}}{24}

(\frac{5}{3 x} + \frac{5}{x} = 1) 3 x

(- \frac{5}{2} - x) (- 3 - x) - 3

\frac{21 d x}{( x ^{2} - 1 ) ^{2}}

What is (s^2+4)*(s^2+4/3) ?
The solution to (s^2+4)*(s^2+4/3) is ((s^2+4)(3s^2+4))/3