What is expand (2x-9)+e^x(2y-cos(y))y'(x) ?

The solution to expand (2x-9)+e^x(2y-cos(y))y'(x) is 2x-9+2e^xy'(x)y-e^xcos(y)y'(x)

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expand (2x-9)+e^x(2y-cos(y))y'(x)

expand

(2 x - 9) + e^{x} (2 y - cos (y)) y^{'} (x)

2 x - 9 + 2 e^{x} y' (x) y - e^{x} cos (y) y' (x)

Solution steps

(2 x - 9) + e^{x} (2 y - cos (y)) y^{'} (x)

Expand

e^{x} y^{'} (x) (2 y - cos (y)) : 2 e^{x} y^{'} (x) y - e^{x} cos (y) y^{'} (x)

= (2 x - 9) + 2 e^{x} y^{'} (x) y - e^{x} cos (y) y^{'} (x)

Remove parentheses:

(a) = a

= 2 x - 9 + 2 e^{x} y^{^{'}} (x) y - e^{x} cos (y) y^{^{'}} (x)

(2 + 1 - x^{2})^{2}

π (1 + x^{2})^{2}

\frac{( n + 1 ) ^{2}}{4 n}

\frac{( n ^{2} - 3 n - 2 ) ^{2}}{4}

\frac{n ( 3 n + 5 )}{3}

What is expand (2x-9)+e^x(2y-cos(y))y'(x) ?
The solution to expand (2x-9)+e^x(2y-cos(y))y'(x) is 2x-9+2e^xy'(x)y-e^xcos(y)y'(x)