What is expand (-u-1)/(2(u^2-u)) ?

The solution to expand (-u-1)/(2(u^2-u)) is (-u-1)/(2u^2-2u)

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expand (-u-1)/(2(u^2-u))

expand

\frac{- u - 1}{2 ( u ^{2} - u )}

\frac{- u - 1}{2 u ^{2} - 2 u}

Solution steps

\frac{- u - 1}{2 ( u ^{2} - u )}

Expand

2 (u^{2} - u) : 2 u^{2} - 2 u

= \frac{- u - 1}{2 u ^{2} - 2 u}

- 4 y (x + \frac{( y - z )}{2})

\frac{x ( x - 1 ) ( x - 12 ) ( x - 21 ) ( x - 23 ) ( x - 24 )}{40824}

y = 2 x + 5

e^{4 t} (t - cos (t) (t))

- \frac{1}{( 1 - j w ) ( j w - 3 ) ^{2}}

What is expand (-u-1)/(2(u^2-u)) ?
The solution to expand (-u-1)/(2(u^2-u)) is (-u-1)/(2u^2-2u)