What is expand ((-x+5)(2-x))/2 ?

The solution to expand ((-x+5)(2-x))/2 is (x^2)/2-(7x)/2+5

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expand ((-x+5)(2-x))/2

expand

\frac{( - x + 5 ) ( 2 - x )}{2}

\frac{x ^{2}}{2} - \frac{7 x}{2} + 5

Solution steps

\frac{( - x + 5 ) ( 2 - x )}{2}

Expand

(- x + 5) (2 - x) : - 7 x + x^{2} + 10

= \frac{- 7 x + x ^{2} + 10}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 7 x + x ^{2} + 10}{2} = - \frac{7 x}{2} + \frac{x ^{2}}{2} + \frac{10}{2}

= - \frac{7 x}{2} + \frac{x ^{2}}{2} + \frac{10}{2}

Divide the numbers:

\frac{10}{2} = 5

= - \frac{7 x}{2} + \frac{x ^{2}}{2} + 5

Rewrite in standard form

= \frac{x ^{2}}{2} - \frac{7 x}{2} + 5

\frac{30}{( s ^{2} + 6 s + 10 ) ( s + 2 )}

cos^{2} (x) (1 + tan (x))

x^{(\frac{3}{2})} (2 x - 7)

sin (3 x) (\frac{1}{sin ^{2} ( 9 )} - \frac{e ^{9 x}}{x})

(\frac{ln ( x )}{3 x ^{3}} + \frac{1}{9 x ^{3}}) \cdot x^{9}

What is expand ((-x+5)(2-x))/2 ?
The solution to expand ((-x+5)(2-x))/2 is (x^2)/2-(7x)/2+5