What is (9/x-x)(9/x+x) ?

The solution to (9/x-x)(9/x+x) is ((-x^2+9)(x^2+9))/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (9/x-x)(9/x+x)

simplify

(\frac{9}{x} - x) (\frac{9}{x} + x)

\frac{( - x ^{2} + 9 ) ( x ^{2} + 9 )}{x ^{2}}

Solution steps

(\frac{9}{x} - x) (\frac{9}{x} + x)

Join

\frac{9}{x} - x : \frac{- x ^{2} + 9}{x}

= \frac{- x ^{2} + 9}{x} (\frac{9}{x} + x)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - x ^{2} + 9 ) ( \frac{9}{x} + x )}{x}

Simplify

(- x^{2} + 9) (\frac{9}{x} + x) : \frac{( - x ^{2} + 9 ) ( x ^{2} + 9 )}{x}

= \frac{\frac{( - x ^{2} + 9 ) ( x ^{2} + 9 )}{x}}{x}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( - x ^{2} + 9 ) ( x ^{2} + 9 )}{xx}

Apply exponent rule:

aa = a^{2}

xx = x^{2}

= \frac{( - x ^{2} + 9 ) ( x ^{2} + 9 )}{x ^{2}}

(3 - 5)^{5}

y (t - sin (t))

\frac{k ( k + 1 )}{( k ^{2} + 1 ) ( k - 1 )}

1 + e^{x} (1 - x)

\frac{1}{2} (t - \frac{1}{2} sin (2 t)) + C

What is (9/x-x)(9/x+x) ?
The solution to (9/x-x)(9/x+x) is ((-x^2+9)(x^2+9))/(x^2)