What is 10(4log_{2}(40)+48log_{2}(1300)) ?

The solution to 10(4log_{2}(40)+48log_{2}(1300)) is 1080+10log_{2}(625*325^{48})

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simplify 10(4log_{2}(40)+48log_{2}(1300))

simplify

10 (4 lo g_{2} (40) + 48 lo g_{2} (1300))

1080 + 10 lo g_{2} (625 \cdot 32 5^{48})

Decimal

5178.13915 \dots

Solution steps

10 (4 lo g_{2} (40) + 48 lo g_{2} (1300))

4 lo g_{2} (40) + 48 lo g_{2} (1300) = 108 + lo g_{2} (625 \cdot 32 5^{48})

= 10 (108 + lo g_{2} (625 \cdot 32 5^{48}))

Expand

10 (108 + lo g_{2} (625 \cdot 32 5^{48})) : 1080 + 10 lo g_{2} (625 \cdot 32 5^{48})

= 1080 + 10 lo g_{2} (625 \cdot 32 5^{48})

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\frac{2 x + 2 h}{x ^{2} + 2 x h + h ^{2} + 1} - \frac{2 x}{x ^{2} + 1}

((3 6^{2} - y^{2}) - 13.5)^{2}

2 (x - y) (1 - \frac{d y}{d x})

What is 10(4log_{2}(40)+48log_{2}(1300)) ?
The solution to 10(4log_{2}(40)+48log_{2}(1300)) is 1080+10log_{2}(625*325^{48})