What is expand 1/12 (x+2)^2(x-3)^2 ?

The solution to expand 1/12 (x+2)^2(x-3)^2 is (x^4}{12}-(x^3)/6-\frac{11x^2)/(12)+x+3

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expand 1/12 (x+2)^2(x-3)^2

expand

\frac{1}{12} (x + 2)^{2} (x - 3)^{2}

\frac{x ^{4}}{12} - \frac{x ^{3}}{6} - \frac{11 x ^{2}}{12} + x + 3

Solution steps

\frac{1}{12} (x + 2)^{2} (x - 3)^{2}

Expand

(x + 2)^{2} : x^{2} + 4 x + 4

= \frac{1}{12} (x^{2} + 4 x + 4) (x - 3)^{2}

= \frac{1}{12} (x - 3)^{2} (x^{2} + 4 x + 4)

Expand

(x - 3)^{2} : x^{2} - 6 x + 9

= \frac{1}{12} (x^{2} - 6 x + 9) (x^{2} + 4 x + 4)

Expand

(x^{2} - 6 x + 9) (x^{2} + 4 x + 4) : x^{4} - 2 x^{3} - 11 x^{2} + 12 x + 36

= \frac{1}{12} (x^{4} - 2 x^{3} - 11 x^{2} + 12 x + 36)

Distribute parentheses

= \frac{1}{12} x^{4} + \frac{1}{12} (- 2 x^{3}) + \frac{1}{12} (- 11 x^{2}) + \frac{1}{12} \cdot 12 x + \frac{1}{12} \cdot 36

Simplify

\frac{1}{12} x^{4} + \frac{1}{12} (- 2 x^{3}) + \frac{1}{12} (- 11 x^{2}) + \frac{1}{12} \cdot 12 x + \frac{1}{12} \cdot 36 : \frac{x ^{4}}{12} - \frac{x ^{3}}{6} - \frac{11 x ^{2}}{12} + x + 3

= \frac{x ^{4}}{12} - \frac{x ^{3}}{6} - \frac{11 x ^{2}}{12} + x + 3

(sin (2 x) sin (x) + cos (4 x) cos (x)) sec (2 x)

- \frac{7}{( s ^{2} - 6 s + 8 ) ( s - 3 )}

(x - 2 + 2) (x + 2 - 2)

11 (17 + 122)

\frac{5 x + 13}{( x - 1 ) ( x + 5 )}

What is expand 1/12 (x+2)^2(x-3)^2 ?
The solution to expand 1/12 (x+2)^2(x-3)^2 is (x^4}{12}-(x^3)/6-\frac{11x^2)/(12)+x+3