What is expand-10x^{2/3}(4x^4-4x^2+5) ?

The solution to expand-10x^{2/3}(4x^4-4x^2+5) is -40x^{14/3}+40x^{8/3}-50x^{2/3}

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expand-10x^{2/3}(4x^4-4x^2+5)

expand

- 10 x^{\frac{2}{3}} (4 x^{4} - 4 x^{2} + 5)

- 40 x^{\frac{14}{3}} + 40 x^{\frac{8}{3}} - 50 x^{\frac{2}{3}}

Solution steps

- 10 x^{\frac{2}{3}} (4 x^{4} - 4 x^{2} + 5)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

- 10 x^{\frac{2}{3}} (4 x^{4} - 4 x^{2} + 5) = - 10 x^{\frac{2}{3}} \cdot 4 x^{4} - 10 x^{\frac{2}{3}} (- 4 x^{2}) - 10 x^{\frac{2}{3}} \cdot 5

= - 10 x^{\frac{2}{3}} \cdot 4 x^{4} - 10 x^{\frac{2}{3}} (- 4 x^{2}) - 10 x^{\frac{2}{3}} \cdot 5

Simplify

- 10 x^{\frac{2}{3}} \cdot 4 x^{4} - 10 x^{\frac{2}{3}} (- 4 x^{2}) - 10 x^{\frac{2}{3}} \cdot 5 : - 40 x^{\frac{14}{3}} + 40 x^{\frac{8}{3}} - 50 x^{\frac{2}{3}}

= - 40 x^{\frac{14}{3}} + 40 x^{\frac{8}{3}} - 50 x^{\frac{2}{3}}

\frac{( x ^{2} - b ) \cdot y \cdot tan ( 7 )}{cos ( x ^{2} ) \cdot π r}

\frac{16 a ^{2} + 12 ab + 9 b ^{3}}{2 ( 16 a ^{2} + 12 ab + 9 b ^{2} )}

(2 + 5) x + y

\frac{1}{( z ^{2} + 4 ) ^{2}}

(x - \frac{5}{9}) (x + 1)

What is expand-10x^{2/3}(4x^4-4x^2+5) ?
The solution to expand-10x^{2/3}(4x^4-4x^2+5) is -40x^{14/3}+40x^{8/3}-50x^{2/3}