What is expand (1-(1/3)x)^2 ?

The solution to expand (1-(1/3)x)^2 is (9-6x+x^2)/9

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expand (1-(1/3)x)^2

expand

(1 - (\frac{1}{3}) x)^{2}

\frac{9 - 6 x + x ^{2}}{9}

Solution steps

(1 - (\frac{1}{3}) x)^{2}

Simplify

1 - (\frac{1}{3}) x : 1 - \frac{1}{3} x

= (1 - \frac{1}{3} x)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(1 - \frac{1}{3} x)^{2} = 1^{2} - 2 \cdot 1 \cdot \frac{1}{3} x + (\frac{1}{3} x)^{2}

= 1^{2} - 2 \cdot 1 \cdot \frac{1}{3} x + (\frac{1}{3} x)^{2}

Simplify

1^{2} - 2 \cdot 1 \cdot \frac{1}{3} x + (\frac{1}{3} x)^{2} : \frac{9 - 6 x + x ^{2}}{9}

= \frac{9 - 6 x + x ^{2}}{9}

\frac{1}{( 4 s ^{2} + 20 s + 29 ) ^{2} ( s ^{2} + 9 )}

(b f - ec - a f + c d + e a - b d)^{2} \cdot (a^{2} + b^{2} + c^{2})

(x - \frac{3}{4}) (x - 2)

(c - 5) (c + 5)

f (x) = \frac{2 x}{( 6 - 3 x ^{2} ) ^{6}}

What is expand (1-(1/3)x)^2 ?
The solution to expand (1-(1/3)x)^2 is (9-6x+x^2)/9