Solution
Solution
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Solution steps
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Simplify
For the solutions are
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Frequently Asked Questions (FAQ)
What are the solutions to the equation sqrt(128)=x^2 ?
The solutions to the equation sqrt(128)=x^2 are x=2\sqrt[4]{2^3},x=-2\sqrt[4]{2^3}Find the zeros of sqrt(128)=x^2
The zeros of sqrt(128)=x^2 are x=2\sqrt[4]{2^3},x=-2\sqrt[4]{2^3}