What is expand (2-i,3+2i,1+3i)(1-3i,2+3i,3-2i) ?

The solution to expand (2-i,3+2i,1+3i)(1-3i,2+3i,3-2i) is

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expand (2-i,3+2i,1+3i)(1-3i,2+3i,3-2i)

expand

(2 - i, 3 + 2 i, 1 + 3 i) (1 - 3 i, 2 + 3 i, 3 - 2 i)

2 \cdot 1 - 2 \cdot 3 i, 2 + 2 \cdot 3 i, 3 - 2 \cdot 2 i - i, 3 \cdot 1 + i, 3 \cdot 3 i, 2 - i, 3 \cdot 3 i, 3 + i, 3 \cdot 2 i + 2 i, 1 \cdot 1 - 2 i, 1 \cdot 3 i, 2 + 2 i, 1 \cdot 3 i, 3 - 2 i, 1 \cdot 2 i + 3 \cdot 1 i - 3 \cdot 3 ii, 2 + 3 \cdot 3 ii, 3 - 3 \cdot 2 ii

Solution steps

(2 - i, 3 + 2 i, 1 + 3 i) (1 - 3 i, 2 + 3 i, 3 - 2 i)

= (2 - 3 i, + 2 \cdot 1 i, + 3 i) (1 - 3 \cdot 2 i, + 3 \cdot 3 i, - 2 i)

Distribute parentheses

= 2 \cdot 1 + 2 (- 3 i, 2) + 2 \cdot 3 i, 3 + 2 (- 2 i) + (- i, 3) \cdot 1 + (- i, 3) (- 3 i, 2) + (- i, 3) \cdot 3 i, 3 + (- i, 3) (- 2 i) + 2 i, 1 \cdot 1 + 2 i, 1 \cdot (- 3 i, 2) + 2 i, 1 \cdot 3 i, 3 + 2 i, 1 \cdot (- 2 i) + 3 i 1 + 3 i (- 3 i, 2) + 3 i 3 i, 3 + 3 i (- 2 i)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= 2 \cdot 1 - 2 \cdot 3 i, 2 + 2 \cdot 3 i, 3 - 2 \cdot 2 i - i, 3 \cdot 1 + i, 3 \cdot 3 i, 2 - i, 3 \cdot 3 i, 3 + i, 3 \cdot 2 i + 2 i, 1 \cdot 1 - 2 i, 1 \cdot 3 i, 2 + 2 i, 1 \cdot 3 i, 3 - 2 i, 1 \cdot 2 i + 3 \cdot 1 i - 3 \cdot 3 ii, 2 + 3 \cdot 3 ii, 3 - 3 \cdot 2 ii

\frac{11}{3} (- e^{- x} x^{2} - 2 e^{- x} x - 2 e^{- x}) (e^{x})

(3 - 7) (4 + 3)

\frac{2 ( π - 8 )}{16}

\frac{1}{( 2 ( n + 1 ) )}

(500 + \frac{c}{3} - c) (100 - \frac{2 c}{15})

What is expand (2-i,3+2i,1+3i)(1-3i,2+3i,3-2i) ?
The solution to expand (2-i,3+2i,1+3i)(1-3i,2+3i,3-2i) is