What is expand 1/(6x)(x^2+2)^3 ?

The solution to expand 1/(6x)(x^2+2)^3 is (x^5)/6+x^3+2x+4/(3x)

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expand 1/(6x)(x^2+2)^3

expand

\frac{1}{6 x} (x^{2} + 2)^{3}

\frac{x ^{5}}{6} + x^{3} + 2 x + \frac{4}{3 x}

Solution steps

\frac{1}{6 x} (x^{2} + 2)^{3}

Expand

(x^{2} + 2)^{3} : x^{6} + 6 x^{4} + 12 x^{2} + 8

= \frac{1}{6 x} (x^{6} + 6 x^{4} + 12 x^{2} + 8)

Distribute parentheses

= \frac{1}{6 x} x^{6} + \frac{1}{6 x} \cdot 6 x^{4} + \frac{1}{6 x} \cdot 12 x^{2} + \frac{1}{6 x} \cdot 8

Simplify

\frac{1}{6 x} x^{6} + \frac{1}{6 x} \cdot 6 x^{4} + \frac{1}{6 x} \cdot 12 x^{2} + \frac{1}{6 x} \cdot 8 : \frac{x ^{5}}{6} + x^{3} + 2 x + \frac{4}{3 x}

= \frac{x ^{5}}{6} + x^{3} + 2 x + \frac{4}{3 x}

p (3, - 5) y q (- 6, 6)

- \frac{2}{( x - 1 ) ( x + h - 1 )}

lo g_{7} (x^{2} + 5) - lo g_{10} (7) (x^{2} + 3)

(x^{\frac{1}{4}} + y^{\frac{1}{4}})^{4}

2 l e f t (a^{2} + 3 a - 4)

What is expand 1/(6x)(x^2+2)^3 ?
The solution to expand 1/(6x)(x^2+2)^3 is (x^5)/6+x^3+2x+4/(3x)