What is expand (ln((cy-fy)/(c(-f+y))))/b ?

The solution to expand (ln((cy-fy)/(c(-f+y))))/b is (ln((cy-yf)/(-cf+cy)))/b

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expand (ln((cy-fy)/(c(-f+y))))/b

expand

\frac{ln ( \frac{cy - f y}{c ( - f + y )} )}{b}

\frac{ln ( \frac{cy - y f}{- c f + cy} )}{b}

Solution steps

\frac{ln ( \frac{cy - f y}{c ( - f + y )} )}{b}

\frac{cy - f y}{c ( - f + y )} = \frac{cy - y f}{- c f + cy}

= \frac{ln ( \frac{cy - f y}{- c f + cy} )}{b}

x (\frac{384}{x - 12} + 8)

\frac{( x - 1 ) ( x + 1 + 2 x )}{2 x ^{2} + 3}

\frac{sinh ( x ) ( x + 1 ) - cosh ( x )}{( x + 1 ) ^{2}}

t (x) x^{^{''}} + (5 t (x) - 2) x^{^{'}} + 5 x

(x + 1 + x)^{2}

What is expand (ln((cy-fy)/(c(-f+y))))/b ?
The solution to expand (ln((cy-fy)/(c(-f+y))))/b is (ln((cy-yf)/(-cf+cy)))/b