What is (k+1/3)*(k-2/3) ?

The solution to (k+1/3)*(k-2/3) is ((3k+1)(3k-2))/9

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simplify (k+1/3)*(k-2/3)

simplify

(k + \frac{1}{3}) \cdot (k - \frac{2}{3})

\frac{( 3 k + 1 ) ( 3 k - 2 )}{9}

Solution steps

(k + \frac{1}{3}) (k - \frac{2}{3})

Simplify

k + \frac{1}{3} : \frac{3 k + 1}{3}

= \frac{3 k + 1}{3} (k - \frac{2}{3})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 3 k + 1 ) ( k - \frac{2}{3} )}{3}

Simplify

(3 k + 1) (k - \frac{2}{3}) : \frac{( 3 k + 1 ) ( k \cdot 3 - 2 )}{3}

= \frac{\frac{( 3 k + 1 ) ( k \cdot 3 - 2 )}{3}}{3}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 3 k + 1 ) ( k \cdot 3 - 2 )}{3 \cdot 3}

Multiply the numbers:

3 \cdot 3 = 9

= \frac{( 3 k + 1 ) ( k \cdot 3 - 2 )}{9}

= \frac{( 3 k + 1 ) ( 3 k - 2 )}{9}

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