What is expand limx\Rightarrow 1(x^3+3x^2-x-3)(x^2-1) ?

The solution to expand limx\Rightarrow 1(x^3+3x^2-x-3)(x^2-1) is

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expand limx\Rightarrow 1(x^3+3x^2-x-3)(x^2-1)

expand

l im x \Rightarrow 1 (x^{3} + 3 x^{2} - x - 3) (x^{2} - 1)

1 i \Rightarrow l m x^{5} x + 1 \cdot 3 i \Rightarrow l m x^{4} x - 1 \cdot 2 i \Rightarrow l m x^{3} x - 1 \cdot 6 i \Rightarrow l m x^{2} x + 1 i \Rightarrow l m xx + 1 \cdot 3 i \Rightarrow l m x

Solution steps

l im x \Rightarrow 1 \cdot (x^{3} + 3 x^{2} - x - 3) (x^{2} - 1)

= 1 i \Rightarrow l m x (x^{3} + 3 x^{2} - x - 3) (x^{2} - 1)

Expand

(x^{3} + 3 x^{2} - x - 3) (x^{2} - 1) : x^{5} + 3 x^{4} - 2 x^{3} - 6 x^{2} + x + 3

= l im x \Rightarrow 1 \cdot (x^{5} + 3 x^{4} - 2 x^{3} - 6 x^{2} + x + 3)

Expand

l im x \Rightarrow 1 \cdot (x^{5} + 3 x^{4} - 2 x^{3} - 6 x^{2} + x + 3) : 1 i \Rightarrow l m x^{5} x + 1 \cdot 3 i \Rightarrow l m x^{4} x - 1 \cdot 2 i \Rightarrow l m x^{3} x - 1 \cdot 6 i \Rightarrow l m x^{2} x + 1 i \Rightarrow l m xx + 1 \cdot 3 i \Rightarrow l m x

= 1 i \Rightarrow l m x^{5} x + 1 \cdot 3 i \Rightarrow l m x^{4} x - 1 \cdot 2 i \Rightarrow l m x^{3} x - 1 \cdot 6 i \Rightarrow l m x^{2} x + 1 i \Rightarrow l m xx + 1 \cdot 3 i \Rightarrow l m x

(z - \frac{1}{2}) (z - \frac{1}{3})

sin (π (x + 1))

(1 - e^{- x}) (1 - e^{- y})

\frac{y ^{5} - ( x ^{2} y ^{3} )}{( x ^{2} + y ^{2} ) ^{2}}

\frac{4 e ^{x} ( - e ^{x} + 4 )}{( 4 + e ^{x} ) ^{3}}

What is expand limx\Rightarrow 1(x^3+3x^2-x-3)(x^2-1) ?
The solution to expand limx\Rightarrow 1(x^3+3x^2-x-3)(x^2-1) is