What are the solutions to the equation x^2+5x+25/4 =0 ?

The solutions to the equation x^2+5x+25/4 =0 are x=-5/2

Find the zeros of x^2+5x+25/4 =0

The zeros of x^2+5x+25/4 =0 are x=-5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 5 x + \frac{25}{4} = 0

x = - \frac{5}{2}

Solution steps

x^{2} + 5 x + \frac{25}{4} = 0

Multiply both sides by

4

4 x^{2} + 20 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 \cdot 25 = 0

x_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 4}

x = \frac{- 20}{2 \cdot 4}

\frac{- 20}{2 \cdot 4} = - \frac{5}{2}

x = - \frac{5}{2}

The solution to the quadratic equation is:

x = - \frac{5}{2}

\frac{6 x ^{2} + 11 x y - 10 y ^{2}}{3 x - 2 y}

b^{2} - 200 = 200

\frac{1}{3} + (- \frac{4}{9})

x^{2} - \frac{1}{2} x - 3

x (8 x - 5) = 13

What are the solutions to the equation x^2+5x+25/4 =0 ?
The solutions to the equation x^2+5x+25/4 =0 are x=-5/2
Find the zeros of x^2+5x+25/4 =0
The zeros of x^2+5x+25/4 =0 are x=-5/2