What is expand ((x^3)/4-1/(x^3))^2 ?

The solution to expand ((x^3)/4-1/(x^3))^2 is (x^{12}-8x^6+16)/(16x^6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((x^3)/4-1/(x^3))^2

expand

(\frac{x ^{3}}{4} - \frac{1}{x ^{3}})^{2}

\frac{x ^{12} - 8 x ^{6} + 16}{16 x ^{6}}

Solution steps

(\frac{x ^{3}}{4} - \frac{1}{x ^{3}})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(\frac{x ^{3}}{4} - \frac{1}{x ^{3}})^{2} = (\frac{x ^{3}}{4})^{2} - 2 \cdot \frac{x ^{3}}{4} \cdot \frac{1}{x ^{3}} + (\frac{1}{x ^{3}})^{2}

= (\frac{x ^{3}}{4})^{2} - 2 \cdot \frac{x ^{3}}{4} \cdot \frac{1}{x ^{3}} + (\frac{1}{x ^{3}})^{2}

Simplify

(\frac{x ^{3}}{4})^{2} - 2 \cdot \frac{x ^{3}}{4} \cdot \frac{1}{x ^{3}} + (\frac{1}{x ^{3}})^{2} : \frac{x ^{12} - 8 x ^{6} + 16}{16 x ^{6}}

= \frac{x ^{12} - 8 x ^{6} + 16}{16 x ^{6}}

(2 x^{\frac{5}{3}} + 3)^{2}

\frac{1}{( ( s ^{2} + 16 ) ^{2} )}

4 (1 - 3)

7 (cos (x) + 7)

\frac{( e ^{2} + 1 ) π}{2}

What is expand ((x^3)/4-1/(x^3))^2 ?
The solution to expand ((x^3)/4-1/(x^3))^2 is (x^{12}-8x^6+16)/(16x^6)