What is expand (1+sin(θ))^3 ?

The solution to expand (1+sin(θ))^3 is 1+3sin(θ)+3sin^2(θ)+sin^3(θ)

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expand (1+sin(θ))^3

expand

(1 + sin (θ))^{3}

1 + 3 sin (θ) + 3 sin^{2} (θ) + sin^{3} (θ)

Solution steps

(1 + sin (θ))^{3}

Apply Perfect Cube Formula:

(a + b)^{3} = a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}

(1 + sin (θ))^{3} = 1^{3} + 3 \cdot 1^{2} sin (θ) + 3 \cdot 1 \cdot sin^{2} (θ) + sin^{3} (θ)

= 1^{3} + 3 \cdot 1^{2} sin (θ) + 3 \cdot 1 \cdot sin^{2} (θ) + sin^{3} (θ)

Simplify

1^{3} + 3 \cdot 1^{2} sin (θ) + 3 \cdot 1 \cdot sin^{2} (θ) + sin^{3} (θ) : 1 + 3 sin (θ) + 3 sin^{2} (θ) + sin^{3} (θ)

= 1 + 3 sin (θ) + 3 sin^{2} (θ) + sin^{3} (θ)

[x - (4 i - 2)] [x - (4 i + 2)] (x - 2)

5 (3 x^{2} - 4 x + 1)^{4} \frac{d}{d x} (3 x^{2} - 4 x + 1)

\frac{27 e ^{x} - 3 e ^{3 x}}{( 3 + e ^{x} ) ^{4}}

(5 + 2 x^{\frac{1}{2}})^{4}

(x + 2 - 3) \cdot (x + 2 + 3)

What is expand (1+sin(θ))^3 ?
The solution to expand (1+sin(θ))^3 is 1+3sin(θ)+3sin^2(θ)+sin^3(θ)