What is expand (-f+g+hcos(α))^2 ?

The solution to expand (-f+g+hcos(α))^2 is f^2-2fg-2fhcos(α)+g^2+h^2cos^2(α)+2ghcos(α)

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expand (-f+g+hcos(α))^2

expand

(- f + g + h cos (α))^{2}

f^{2} - 2 f g - 2 f h cos (α) + g^{2} + h^{2} cos^{2} (α) + 2 g h cos (α)

Solution steps

(- f + g + h cos (α))^{2}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(- f + g + h cos (α))^{2} = (- f + g + h cos (α)) (- f + g + h cos (α))

= (- f + g + h cos (α)) (- f + g + h cos (α))

Distribute parentheses

= - f (- f) - f g - f h cos (α) + g (- f) + gg + g h cos (α) + h cos (α) (- f) + h cos (α) g + h cos (α) h cos (α)

Simplify

- f (- f) - f g - f h cos (α) + g (- f) + gg + g h cos (α) + h cos (α) (- f) + h cos (α) g + h cos (α) h cos (α) : f^{2} - 2 f g - 2 f h cos (α) + g^{2} + h^{2} cos^{2} (α) + 2 g h cos (α)

= f^{2} - 2 f g - 2 f h cos (α) + g^{2} + h^{2} cos^{2} (α) + 2 g h cos (α)

7 - 3 i + 7 - 3 i

(3 - 42) (5 - 62)

(2 u^{4} x^{4} + x^{4}) d x

\frac{2 x ^{2} - 3 + x + 5 ( x + 2 )}{x + 2}

e^{2 i θ} (cos (2 θ) - i sin (2 θ))

What is expand (-f+g+hcos(α))^2 ?
The solution to expand (-f+g+hcos(α))^2 is f^2-2fg-2fhcos(α)+g^2+h^2cos^2(α)+2ghcos(α)