What is expand ((x-2)(x-3))/2 ?

The solution to expand ((x-2)(x-3))/2 is (x^2)/2-(5x)/2+3

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expand ((x-2)(x-3))/2

expand

\frac{( x - 2 ) ( x - 3 )}{2}

\frac{x ^{2}}{2} - \frac{5 x}{2} + 3

Solution steps

\frac{( x - 2 ) ( x - 3 )}{2}

Expand

(x - 2) (x - 3) : x^{2} - 5 x + 6

= \frac{x ^{2} - 5 x + 6}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 5 x + 6}{2} = \frac{x ^{2}}{2} - \frac{5 x}{2} + \frac{6}{2}

= \frac{x ^{2}}{2} - \frac{5 x}{2} + \frac{6}{2}

Divide the numbers:

\frac{6}{2} = 3

= \frac{x ^{2}}{2} - \frac{5 x}{2} + 3

\frac{s + 2}{( ( s + 2 ) ^{2} + 9 ) \cdot ( s + 2 ) ^{2}}

\frac{( k - 1 ) ( 3 k ^{6} - k ^{5} - k ^{4} + k ^{3} + k ^{2} + k + 1 )}{k ^{4}}

\frac{2 sin ( x ) - sin ( 2 x )}{2 cos ( x ) ( 1 - cos ( x ) )}

(5 x + 8 x^{3} - x^{2} + 9) l e f t (4 x - 5)

1 - 2 (x + h) - 1 - 2 x

What is expand ((x-2)(x-3))/2 ?
The solution to expand ((x-2)(x-3))/2 is (x^2)/2-(5x)/2+3