What is expand (3x+7)/((4x+2)(x-1)) ?

The solution to expand (3x+7)/((4x+2)(x-1)) is (3x+7)/(4x^2-2x-2)

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expand (3x+7)/((4x+2)(x-1))

expand

\frac{3 x + 7}{( 4 x + 2 ) ( x - 1 )}

\frac{3 x + 7}{4 x ^{2} - 2 x - 2}

Solution steps

\frac{3 x + 7}{( 4 x + 2 ) ( x - 1 )}

Expand

(4 x + 2) (x - 1) : 4 x^{2} - 2 x - 2

= \frac{3 x + 7}{4 x ^{2} - 2 x - 2}

(4 x + 1) (6 x + 8)

\frac{d ^{2}}{d x ^{2}} ((y (t, x)) (1 + t^{2}))

(5 - 6 x)^{2}

\frac{( 5 - x ) ^{7} ( x - 13 ) ^{2}}{( x ^{2} + 7 ) ^{2}}

x^{2} + (- y - 2)^{2} 0.2

What is expand (3x+7)/((4x+2)(x-1)) ?
The solution to expand (3x+7)/((4x+2)(x-1)) is (3x+7)/(4x^2-2x-2)