What is expand-(16(2x^2+1))/(x+2) ?

The solution to expand-(16(2x^2+1))/(x+2) is -(32x^2+16)/(x+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-(16(2x^2+1))/(x+2)

expand

- \frac{16 ( 2 x ^{2} + 1 )}{x + 2}

- \frac{32 x ^{2} + 16}{x + 2}

Solution steps

- \frac{16 ( 2 x ^{2} + 1 )}{x + 2}

Expand

16 (2 x^{2} + 1) : 32 x^{2} + 16

= - \frac{32 x ^{2} + 16}{x + 2}

(x^{2} + 4)^{3} ln (3 x)

- 3 (2 - 4) + 9 (2)^{'}

2 \cdot (2 + \frac{2}{11})

\frac{( 5 x )}{( s ^{2} + 4 ) ( 12 x + 7 )}

\frac{10 x + 1}{3 x ^{2}}

What is expand-(16(2x^2+1))/(x+2) ?
The solution to expand-(16(2x^2+1))/(x+2) is -(32x^2+16)/(x+2)