What is expand 1/((x^2-x+1)(x^2-x+2)) ?

The solution to expand 1/((x^2-x+1)(x^2-x+2)) is 1/(x^4-2x^3+4x^2-3x+2)

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expand 1/((x^2-x+1)(x^2-x+2))

expand

\frac{1}{( x ^{2} - x + 1 ) ( x ^{2} - x + 2 )}

\frac{1}{x ^{4} - 2 x ^{3} + 4 x ^{2} - 3 x + 2}

Solution steps

\frac{1}{( x ^{2} - x + 1 ) ( x ^{2} - x + 2 )}

Expand

(x^{2} - x + 1) (x^{2} - x + 2) : x^{4} - 2 x^{3} + 4 x^{2} - 3 x + 2

= \frac{1}{x ^{4} - 2 x ^{3} + 4 x ^{2} - 3 x + 2}

\frac{1}{( s + 10 ) ( s + 2 ) ^{2}}

4 (8 e + 28)

\frac{1}{( x - 3 ) ( x + 3 )}

(3 + M i)^{2}

A (0, 4) y B (- 4, - 2)

What is expand 1/((x^2-x+1)(x^2-x+2)) ?
The solution to expand 1/((x^2-x+1)(x^2-x+2)) is 1/(x^4-2x^3+4x^2-3x+2)