What is expand (2/3 (x-3))^2+4 ?

The solution to expand (2/3 (x-3))^2+4 is (4x^2)/9-(8x)/3+8

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expand (2/3 (x-3))^2+4

expand

(\frac{2}{3} (x - 3))^{2} + 4

\frac{4 x ^{2}}{9} - \frac{8 x}{3} + 8

Solution steps

(\frac{2}{3} (x - 3))^{2} + 4

(\frac{2}{3} (x - 3))^{2} = \frac{2 ^{2}}{3 ^{2}} (x^{2} - 6 x + 9)

= \frac{2 ^{2}}{3 ^{2}} (x^{2} - 6 x + 9) + 4

\frac{2 ^{2}}{3 ^{2}} = \frac{4}{9}

= \frac{4}{9} (x^{2} - 6 x + 9) + 4

Expand

\frac{4}{9} (x^{2} - 6 x + 9) : \frac{4 x ^{2}}{9} - \frac{8 x}{3} + 4

= \frac{4 x ^{2}}{9} - \frac{8 x}{3} + 4 + 4

Add the numbers:

4 + 4 = 8

= \frac{4 x ^{2}}{9} - \frac{8 x}{3} + 8

(5 x - 3) (4 + \frac{3}{x ^{2}})

(- 0.5 + 0.5 i)^{5}

\frac{m ( m + 1 )}{2} + (m + 1)

\frac{4}{( x + 1 ) ^{3}}

1001 \times 34

What is expand (2/3 (x-3))^2+4 ?
The solution to expand (2/3 (x-3))^2+4 is (4x^2)/9-(8x)/3+8