What is expand 1/((s-1)(s-2)(s+6)) ?

The solution to expand 1/((s-1)(s-2)(s+6)) is 1/(s^3+3s^2-16s+12)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 1/((s-1)(s-2)(s+6))

expand

\frac{1}{( s - 1 ) ( s - 2 ) ( s + 6 )}

\frac{1}{s ^{3} + 3 s ^{2} - 16 s + 12}

Solution steps

\frac{1}{( s - 1 ) ( s - 2 ) ( s + 6 )}

Expand

(s - 1) (s - 2) (s + 6) : s^{3} + 3 s^{2} - 16 s + 12

= \frac{1}{s ^{3} + 3 s ^{2} - 16 s + 12}

- 2 \cdot (2 + 2 - 2)

(a + ib)^{2} + a + ib

(2 sin (x) - 2) (2 cos (x) + 1)

\frac{- 5}{7} (x + 8)

\frac{- 1 + 65}{8}

What is expand 1/((s-1)(s-2)(s+6)) ?
The solution to expand 1/((s-1)(s-2)(s+6)) is 1/(s^3+3s^2-16s+12)