What is expand ((((2y+3)/2))/(2))^2 ?

The solution to expand ((((2y+3)/2))/(2))^2 is (y^2)/4+(3y)/4+9/16

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expand ((((2y+3)/2))/(2))^2

expand

(\frac{( \frac{2 y + 3}{2} )}{2})^{2}

\frac{y ^{2}}{4} + \frac{3 y}{4} + \frac{9}{16}

Solution steps

(\frac{\frac{2 y + 3}{2}}{2})^{2}

\frac{\frac{2 y + 3}{2}}{2} = \frac{2 y + 3}{4}

= (\frac{2 y + 3}{4})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 2 y + 3 ) ^{2}}{4 ^{2}}

(2 y + 3)^{2} = 4 y^{2} + 12 y + 9

= \frac{4 y ^{2} + 12 y + 9}{4 ^{2}}

4^{2} = 16

= \frac{4 y ^{2} + 12 y + 9}{16}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 y ^{2} + 12 y + 9}{16} = \frac{4 y ^{2}}{16} + \frac{12 y}{16} + \frac{9}{16}

= \frac{4 y ^{2}}{16} + \frac{12 y}{16} + \frac{9}{16}

Cancel

\frac{4 y ^{2}}{16} : \frac{y ^{2}}{4}

= \frac{y ^{2}}{4} + \frac{12 y}{16} + \frac{9}{16}

Cancel

\frac{12 y}{16} : \frac{3 y}{4}

= \frac{y ^{2}}{4} + \frac{3 y}{4} + \frac{9}{16}

(x - 1 + 3) \cdot (x - 1 - 3)

(5 + 2 i)^{4}

5 1 + \frac{x}{4}

(5 + 2 i)^{6}

\frac{1}{s ^{2} ( s ^{2} + 6 )}

What is expand ((((2y+3)/2))/(2))^2 ?
The solution to expand ((((2y+3)/2))/(2))^2 is (y^2)/4+(3y)/4+9/16