What is expand (-2x^2+1)/((x^2+1)^{5/2)} ?

The solution to expand (-2x^2+1)/((x^2+1)^{5/2)} is -(2x^2)/((x^2+1)^{5/2)}+1/((x^2+1)^{5/2)}

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expand (-2x^2+1)/((x^2+1)^{5/2)}

expand

\frac{- 2 x ^{2} + 1}{( x ^{2} + 1 ) ^{\frac{5}{2}}}

- \frac{2 x ^{2}}{( x ^{2} + 1 ) ^{\frac{5}{2}}} + \frac{1}{( x ^{2} + 1 ) ^{\frac{5}{2}}}

Solution steps

\frac{- 2 x ^{2} + 1}{( x ^{2} + 1 ) ^{\frac{5}{2}}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 2 x ^{2} + 1}{( x ^{2} + 1 ) ^{\frac{5}{2}}} = - \frac{2 x ^{2}}{( x ^{2} + 1 ) ^{\frac{5}{2}}} + \frac{1}{( x ^{2} + 1 ) ^{\frac{5}{2}}}

= - \frac{2 x ^{2}}{( x ^{2} + 1 ) ^{\frac{5}{2}}} + \frac{1}{( x ^{2} + 1 ) ^{\frac{5}{2}}}

\frac{1}{s ^{2} ( s + 3 ) ^{2}}

(3 u - \frac{3}{7} v)^{2}

\frac{( x + 3 ) ^{2}}{( x - 2 )}

\frac{a}{b ( c - d r )}

(cot (θ) + 1) (sec (θ) - 1)

What is expand (-2x^2+1)/((x^2+1)^{5/2)} ?
The solution to expand (-2x^2+1)/((x^2+1)^{5/2)} is -(2x^2)/((x^2+1)^{5/2)}+1/((x^2+1)^{5/2)}